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3n^2-15n-450=0
a = 3; b = -15; c = -450;
Δ = b2-4ac
Δ = -152-4·3·(-450)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-75}{2*3}=\frac{-60}{6} =-10 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+75}{2*3}=\frac{90}{6} =15 $
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